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  4. When a positive q charge is taken from lower potential to a higher potential point, then its potential energy will

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Q. When a positive $q$ charge is taken from lower potential to a higher potential point, then its potential energy will

Electrostatic Potential and Capacitance

Solution:

$\Delta P . E .=$ Work done by external agent
$=\left(V_{f} q-V_{i} q\right)$
$V_{f} > V_{i} \Rightarrow \Delta P . E .>0 i.e. P.E.$ will increase