When a dielectric is placed in an electric field, the electric field inside a dielectric

Question

When a dielectric is placed in an electric field, the electric field inside a dielectric (A) increases (B) decreases (C) constant (D) zero

Tardigrade Admin · Accepted Answer

An electric field (Ei) is induced inside the dielectric in a direction opposite to the external field (E0) due to polarisation. On account of this, the net electric field (E) inside the slab is less than the external field as E=E0-Ei.

Q. When a dielectric is placed in an electric field, the electric field inside a dielectric

increases

decreases

constant

zero

An electric field $(E_{i})$ is induced inside the dielectric in a direction opposite to the external field $(E_{0})$ due to polarisation. On account of this, the net electric field $(E)$ inside the slab is less than the external field as $E = E_{0} - E_{i}$ .

Q. When a dielectric is placed in an electric field, the electric field inside a dielectric

increases

decreases

constant

zero

An electric field (Ei​) is induced inside the dielectric in a direction opposite to the external field (E0​) due to polarisation. On account of this, the net electric field (E) inside the slab is less than the external field as E=E0​−Ei​.

An electric field $(E_{i})$ is induced inside the dielectric in a direction opposite to the external field $(E_{0})$ due to polarisation. On account of this, the net electric field $(E)$ inside the slab is less than the external field as $E = E_{0} - E_{i}$ .