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Q.
When a dielectric is placed in an electric field, the electric field inside a dielectric
Electrostatic Potential and Capacitance
Solution:
An electric field $\left(E_{i}\right)$ is induced inside the dielectric in a direction opposite to the external field $\left(E_{0}\right)$ due to polarisation. On account of this, the net electric field $(E)$ inside the slab is less than the external field as $E=E_{0}-E_{i}$.