When 2-butyne reacts with sodamide in an inert solvent in the presence of dilute HCl, the product formed is:

Question

When 2-butyne reacts with sodamide in an inert solvent in the presence of dilute HCl, the product formed is: (A) n-Butane (B) 2-Butene (C) 1-Butyne (D) 1 -Propyne

Tardigrade Admin · Accepted Answer

When 2-butyne is heated with NaNH2 in an inert solvent, the sodium derivative of but-1-yne which is converted into but-1-yne by the action of dil. HCl. CH3 - C ≡ C - CH3 + NaNH2 xrightarrow textparaffin NH3 + CH3CH2C ≡ CNa xrightarrowdil. HCl underset1- textbutyneCH3CH2C≡ CH

Q. When $2$ -butyne reacts with sodamide in an inert solvent in the presence of dilute $H Cl$ , the product formed is:

$n$ -Butane

$2$ -Butene

$1$ -Butyne

$1$ -Propyne

Q. When 2-butyne reacts with sodamide in an inert solvent in the presence of dilute HCl, the product formed is:

n-Butane

2-Butene

1-Butyne

1 -Propyne

When 2-butyne is heated with NaNH2​ in an inert solvent, the sodium derivative of but-1-yne which is converted into but-1-yne by the action of dil. HCl. CH3​−C≡C−CH3​+NaNH2​paraffin​ NH3​+CH3​CH2​C≡CNadil.HCl​1−butyneCH3​CH2​C≡CH​

Q. When $2$ -butyne reacts with sodamide in an inert solvent in the presence of dilute $H Cl$ , the product formed is:

$n$ -Butane

$2$ -Butene

$1$ -Butyne

$1$ -Propyne