1. Tardigrade
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  4. When 2-butyne reacts with sodamide in an inert solvent in the presence of dilute HCl, the product formed is:

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Q. When $2$-butyne reacts with sodamide in an inert solvent in the presence of dilute $HCl$, the product formed is:

Hydrocarbons

Solution:

When $2$-butyne is heated with $NaNH_2$ in an inert solvent, the sodium derivative of but-$1$-yne which is converted into but-$1$-yne by the action of dil. $HCl$. $ CH_3 - C \equiv C - CH_3 + NaNH_2 \xrightarrow{\text{paraffin}}$
$NH_3 + CH_3CH_2C \equiv CNa \xrightarrow{dil. HCl} \underset{1-\text{butyne}}{CH_3CH_2C\equiv CH}$