Question

When $2^{301}$ is divided by $5,$ then find least positive remainder.

Answer 1

Answer: 2

$2^{301}=2.2^{300}=2.4^{150}=2{\left(5-1\right)}^{150}$
Here all terms, except last term are divisible by $5$
$\therefore$ Remainder $=2$ (last term) $=2{\left(-1\right)}^{150}=2$