Question

When $2^{301}$ is divided by $5,$ then find least positive remainder.

Answer 1

$2^{301}=2.2^{300}=2.4^{150}=2\left(5 - 1\right)^{150}$
Here all terms, except last term are divisible by $5$
$\therefore $ Remainder $=2$ (last term) $=2\left(- 1\right)^{150}=2$