When 100 g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, nCH 2= CH 2 arrow( CH 2- CH 2) n is :

Question

When 100 g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, nCH 2= CH 2 arrow( CH 2- CH 2) n is : (A)  (n/2)g  (B) 100 g (C)  (100/n)g  (D) 100 ng

Tardigrade Admin · Accepted Answer

When 100 g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, nCH 2= CH 2 arrow( CH 2- CH 2) n is 100 g, because entire mass of ethylene is converted to polyethylene as there is no addition, elimination or condensation of simple molecules.

Q. When $100 g$ of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, $n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}$ is :

$\frac{n}{2} g$

$100 g$

$\frac{100}{n} g$

$100 n g$

Q. When 100g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, nCH2​=CH2​→(CH2​−CH2​)n​ is :

2n​g

100g

n100​g

100ng

When 100g of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, nCH2​=CH2​→(CH2​−CH2​)n is 100g, because entire mass of ethylene is converted to polyethylene as there is no addition, elimination or condensation of simple molecules.

Q. When $100 g$ of ethylene polymerises entirely to polyethene, the weight of polyethene formed as per the equation, $n C H_{2} = C H_{2} \to (C H_{2} - C H_{2})_{n}$ is :

$\frac{n}{2} g$

$100 g$

$\frac{100}{n} g$

$100 n g$