When 0.1molMnO42 - is oxidised the quantity of electricity required to completely oxidise MnO42 - to MnO4- is :

Question

When 0.1molMnO42 - is oxidised the quantity of electricity required to completely oxidise MnO42 - to MnO4- is : (A) 96500C (B) 2× 96500C (C) 9650C (D) 96.50C

Tardigrade Admin · Accepted Answer

overset+ 6 underlineMn O4- 2 arrow overset+ 7 underlineMnO4-+e- 0.1mole 0.1mole charge required =0.1F=0.1× 96500 =9650C

Q. When $0.1 m o lM n O_{4}^{2 -}$ is oxidised the quantity of electricity required to completely oxidise $M n O_{4}^{2 -}$ to $M n O_{4}^{-}$ is :

$96500 C$

$2 \times 96500 C$

$9650 C$

$96.50 C$

$\underline{M n} O_{4}^{- 2} + 6$ $\to \underline{M n} + 7 O_{4}^{-} + e^{-}$
$0.1 m o l e$ $0.1 m o l e$
charge required $= 0.1 F = 0.1 \times 96500$
$= 9650 C$

Q. When 0.1molMnO42−​ is oxidised the quantity of electricity required to completely oxidise MnO42−​ to MnO4−​ is :

96500C

2×96500C

9650C

96.50C