Question

When $0.1molMnO_{4}^{2 -}$ is oxidised the quantity of electricity required to completely oxidise $MnO_{4}^{2 -}$ to $MnO_{4}^{-}$ is :

• A. $96500C$
• B. $2\times 96500C$
• C. $9650C$
• D. $96.50C$

Answer 1

Answer: (C)

$\overset{+ 6}{\underline{Mn} O_{4}^{- 2}}$ $ \rightarrow \overset{+ 7}{\underline{Mn}}O_{4}^{-}+e^{-}$
$0.1mole$ $0.1mole$
charge required $=0.1F=0.1\times 96500$
$=9650C$