Question

When $0.01mol$ of an organic compound containing $60\%$ carbon was burnt completely, $4.4g$ of $C{O}_2$ was produced. The molar mass of compound is ___$gmo{l}^{-1}$ (Nearest integer)

Answer 1

Answer: 200

Let $M$ is the molar mass of the compound $(g/mol)$
mass of compound $=0.01Mgm$
mass of carbon $=0.01M\times \frac{60}{100}$
moles of carbon $=\frac{0.01M}{12}\times \frac{60}{100}$
moles of $C{O}_2$ from combustion $=\frac{4.4}{44}=$ moles of carbon
$\frac{0.01M}{12}\times \frac{60}{100}=\frac{4.4}{44}$
$M=\frac{4.4}{44}\times \frac{100}{60}\times \frac{12}{0.01}=200gm/mol$