Question

When $0.01\, mol$ of an organic compound containing $60 \%$ carbon was burnt completely, $4.4 \,g$ of $CO _2$ was produced. The molar mass of compound is ___$g \,mol ^{-1}$ (Nearest integer)

Answer 1

Let $M$ is the molar mass of the compound $( g / mol )$
mass of compound $=0.01 \,Mgm$
mass of carbon $=0.01 M \times \frac{60}{100}$
moles of carbon $=\frac{0.01 M }{12} \times \frac{60}{100}$
moles of $CO _2$ from combustion $=\frac{4.4}{44}=$ moles of carbon
$\frac{0.01 M }{12} \times \frac{60}{100}=\frac{4.4}{44}$
$M =\frac{4.4}{44} \times \frac{100}{60} \times \frac{12}{0.01}=200\, gm / mol$