Question

What will be the pH value of 0.05 M $Ba{(OH)}_2$ solution?

• A. 12
• B. 13
• C. 1
• D. 12.96

Answer 1

Answer: (B)

$0.05MBa{(OH)}_2$ Solution $\cong 2\times 0.05NBa{(OH)}_2$ $\cong 0.10NBa{(OH)}_2$ $\therefore$ $pOH=-\log [O{H}^{-}]$ $=-\log (0.10)=1$ $pH=14-pOH$ $=14-1=13$