Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. What will be the pH value of 0.05 M $ Ba{{(OH)}_{2}} $ solution?

MGIMS WardhaMGIMS Wardha 2004

Solution:

$ 0.05\text{ }M\text{ }Ba{{(OH)}_{2}} $ Solution $ \cong 2\times 0.05N\,Ba{{(OH)}_{2}} $ $ \cong 0.10N\,Ba{{(OH)}_{2}} $ $ \therefore $ $ pOH=-\log [O{{H}^{-}}] $ $ =-\log (0.10)=1 $ $ pH=14-pOH $ $ =14-1=13 $