What will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH in the ratio 2: 1 by volume?

Question

What will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH in the ratio 2: 1 by volume? (A) 0.4 N (B) 0.5 N (C) 1.05 N (D) 0.15 N

Tardigrade Admin · Accepted Answer

N=(N1 V1+N2 V2/V1+V2)=(0.45 × 2+0.6 × 1/2+1)=(1.5/3)=0.5 N

Q. What will be the normality of a solution obtained by mixing $0.45 N$ and $0.60 N N a O H$ in the ratio $2 : 1$ by volume?

0.4 N

0.5 N

1.05 N

0.15 N

$N = \frac{N _{1} V _{1} + N _{2} V _{2}}{V _{1} + V _{2}} = \frac{0.45 \times 2 + 0.6 \times 1}{2 + 1} = \frac{1.5}{3} = 0.5 N$

Q. What will be the normality of a solution obtained by mixing 0.45N and 0.60NNaOH in the ratio 2:1 by volume?