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  4. What will be the normality of a solution obtained by mixing 0.45 N and 0.60 N NaOH in the ratio 2: 1 by volume?

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Q. What will be the normality of a solution obtained by mixing $0.45\, N$ and $0.60\, N \,NaOH$ in the ratio $2 : 1$ by volume?

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Solution:

$N=\frac{N_{1} V_{1}+N_{2} V_{2}}{V_{1}+V_{2}}=\frac{0.45 \times 2+0.6 \times 1}{2+1}=\frac{1.5}{3}=0.5 \,N$