What will be the molar conductance ' ∧ ', if resistivity is ' x ' for 0.1 N H 2 SO 4 solution?

Question

What will be the molar conductance ' ∧ ', if resistivity is ' x ' for 0.1 N H 2 SO 4 solution? (A) ∧=(x × 1000/0.1) (B) ∧=(2 × 1000/x × 0.1) (C) ∧=(x × 1000/0.5) (D) ∧=(0.5/1000 x )

Tardigrade Admin · Accepted Answer

∧m =(K × 1000/M) =(1/ρ) × (1000/ M ) =(1000 × 2/x × 0.1) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/44c1762fc6c6080473db7cbedbda7cee-.png" />

Q. What will be the molar conductance ' $\land$ ', if resistivity is ' $x$ ' for $0.1 N H_{2} S O_{4}$ solution?

$\land = \frac{x \times 1000}{0.1}$

$\land = \frac{2 \times 1000}{x \times 0.1}$

$\land = \frac{x \times 1000}{0.5}$

$\land = \frac{0.5}{1000 x}$

$\land_{m} = \frac{K \times 1000}{M}$
$= \frac{1}{ρ} \times \frac{1000}{M}$
$= \frac{1000 \times 2}{x \times 0.1}$

Q. What will be the molar conductance ' ∧ ', if resistivity is ' x ' for 0.1NH2​SO4​ solution?

∧=0.1x×1000​

∧=x×0.12×1000​

∧=0.5x×1000​

∧=1000x0.5​