Question

What will be the molar conductance ' $\wedge$ ', if resistivity is ' $x$ ' for $0.1 N H _{2} SO _{4}$ solution?

• A. $\wedge=\frac{x \times 1000}{0.1}$
• B. $\wedge=\frac{2 \times 1000}{x \times 0.1}$
• C. $\wedge=\frac{x \times 1000}{0.5}$
• D. $\wedge=\frac{0.5}{1000 x }$

Answer 1

Answer: (B)

$ \wedge_{m} =\frac{K \times 1000}{M} $
$=\frac{1}{\rho} \times \frac{1000}{ M } $
$=\frac{1000 \times 2}{x \times 0.1}$