What will be the maximum value of Sigma (n + l + m) for all unpaired electrons of chlorine in its second excited state?

Question

What will be the maximum value of Sigma (n + l + m) for all unpaired electrons of chlorine in its second excited state? (A) 25 (B) 20 (C) 28 (D) 27

Tardigrade Admin · Accepted Answer

Cl17 (second excited state) =3p33d2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-y7yy535mqoujlmiu.jpg" />

Q. What will be the maximum value of $Σ (n + l + m)$ for all unpaired electrons of chlorine in its second excited state?

25

20

28

27

$C l_{17}$ (second excited state) $= 3 p^{3} 3 d^{2}$

Q. What will be the maximum value of Σ(n+l+m) for all unpaired electrons of chlorine in its second excited state?

25

20

28

27

Cl17​ (second excited state) =3p33d2

Q. What will be the maximum value of $Σ (n + l + m)$ for all unpaired electrons of chlorine in its second excited state?

$C l_{17}$ (second excited state) $= 3 p^{3} 3 d^{2}$