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  4. What will be the maximum value of Sigma (n + l + m) for all unpaired electrons of chlorine in its second excited state?

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Q. What will be the maximum value of $\Sigma \left(n + l + m\right)$ for all unpaired electrons of chlorine in its second excited state?

NTA AbhyasNTA Abhyas 2022

Solution:

$Cl_{17}$ (second excited state) $=3p^{3}3d^{2}$
Solution