What will be the mass of a particle if uncertainty in its position is 10-8 m and velocity is 5.26 × 10-25 m s-1?

Question

What will be the mass of a particle if uncertainty in its position is 10-8 m and velocity is 5.26 × 10-25 m s-1? (A) 0.01 kg (B) 0.1 kg (C) 1 kg (D) 10 kg

Tardigrade Admin · Accepted Answer

Δ x ⋅ mΔ v=(h/4π) 10-8 m× m×5.26×10-25 m s-1 =(6.626 × 10-34 J s/4 ×3.14) m=(6.626 × 10-34 J s/4 × 3.14 × 10-8 m × 5.26 × 10-25 m s-1) =0.01 kg

Q. What will be the mass of a particle if uncertainty in its position is $1 0^{- 8} m$ and velocity is $5.26 \times 1 0^{- 25} m s^{- 1}$ ?

$0.01 k g$

$0.1 k g$

$1 k g$

$10 k g$

$Δ x \cdot m Δ v = \frac{h}{4 π}$
$1 0^{- 8} m \times m \times 5.26 \times 1 0^{- 25} m s^{- 1}$
$= \frac{6.626 \times 1 0 ^{- 34} J s}{4 \times 3.14}$
$m = \frac{6.626 \times 1 0 ^{- 34} J s}{4 \times 3.14 \times 1 0 ^{- 8} m \times 5.26 \times 1 0 ^{- 25} m s ^{- 1}}$
$= 0.01 k g$

Q. What will be the mass of a particle if uncertainty in its position is 10−8m and velocity is 5.26×10−25ms−1?

0.01kg

0.1kg

1kg

10kg