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Q. What will be the mass of a particle if uncertainty in its position is $10^{-8}\, m$ and velocity is $5.26 \times 10^{-25}\, m\,s^{-1}$?

Structure of Atom

Solution:

$\Delta x \cdot m\Delta v=\frac{h}{4\pi}$
$10^{-8}\,m\times m\times5.26\times10^{-25}\,m\,s^{-1}$
$=\frac{6.626 \times 10^{-34}\,J\,s}{4 \times3.14}$
$m=\frac{6.626 \times 10^{-34}\,J\,s}{4 \times 3.14 \times 10^{-8}\,m \times 5.26 \times 10^{-25} \,m\,s^{-1}}$
$=0.01\,kg $