What will be the angle of diffraction for the first minimum due to Fraunhoffer diffraction with sources of light of wavelength 550 nm and slit of width 0.55 mm ?

Question

What will be the angle of diffraction for the first minimum due to Fraunhoffer diffraction with sources of light of wavelength 550 nm and slit of width 0.55 mm ? (A) 1 rad (B) 0.1 rad (C) 0.01 rad (D) 0.001 rad

Tardigrade Admin · Accepted Answer

Here d sin θ = n λ. For n = 1, we fine sin θ = (λ/d) = (550 × 10-9/0.55 × 10-3) = 10-3 rad.

Q. What will be the angle of diffraction for the first minimum due to Fraunhoffer diffraction with sources of light of wavelength 550 nm and slit of width 0.55 mm ?

1 rad

0.1 rad

0.01 rad

0.001 rad

Here $d$ sin $θ = n λ$ .
For $n$ = 1, we fine sin $θ = \frac{λ}{d} = \frac{550 \times 1 0 ^{- 9}}{0.55 \times 1 0 ^{- 3}} = 1 0^{- 3}$ rad.

Q. What will be the angle of diffraction for the first minimum due to Fraunhoffer diffraction with sources of light of wavelength 550 nm and slit of width 0.55 mm ?

1 rad

0.1 rad

0.01 rad

0.001 rad

Here d sin θ=nλ. For n = 1, we fine sin θ=dλ​=0.55×10−3550×10−9​=10−3 rad.

Here $d$ sin $θ = n λ$ .
For $n$ = 1, we fine sin $θ = \frac{λ}{d} = \frac{550 \times 1 0 ^{- 9}}{0.55 \times 1 0 ^{- 3}} = 1 0^{- 3}$ rad.