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Q.
What will be the angle of diffraction for the first minimum due to Fraunhoffer diffraction with sources of light of wavelength 550 nm and slit of width 0.55 mm ?
Solution:
Here $d$ sin $\theta = n\, \lambda$.
For $n$ = 1, we fine sin $\theta = \frac{\lambda}{d} = \frac{550 \times 10^{-9}}{0.55 \times 10^{-3}} = 10^{-3}$ rad.