Question

What will be order of reaction and rate constant for a chemical change having $t_{50\%}$ vs. log conc. (a) curve as

• A. 0,1
• B. 1,1
• C. 2,2
• D. 3,1

Answer 1

Answer: (A)

For a reaction, $t_{1/2}\times a^{1-n}=K(.a{)}^{1-n}$

$\log t_{1/2}=(1-n)\log a+\log k$

$(y=mx+c)C=0.$ So, $\log K=0$ and $K=1$

$1-n=\tan 45^{\circ }$

$\Rightarrow n=0$