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Q. What will be order of reaction and rate constant for a chemical change having $t_{50 \%}$ vs. log conc. (a) curve as
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Chemical Kinetics

Solution:

For a reaction, $t_{1 / 2} \times a^{1-n}=K(. a)^{1-n}$

$\log\, t_{1 / 2}=(1-n) \log \,a+\log\, k$

$(y=m x+c) C=0 .$ So, $\log K=0$ and $K=1$

$1-n=\tan 45^{\circ} $

$\Rightarrow n=0$