What volume of 3 molar HNO3 is needed to oxidise 8 g of Fe2+ to Fe3+? HNO3 → NO

Question

What volume of 3 molar HNO3 is needed to oxidise 8 g of Fe2+ to Fe3+? HNO3 → NO (A) 8 ml (B) 15.87 ml (C) 32 ml (D) 64 ml

Tardigrade Admin · Accepted Answer

The balanced reaction is underset overset31/73Fe2+ + 4H+ + NO-3 → 3Fe3+ + underset overset13 VNO + 2H2O ∴ (3/17)=(1/3V) ⇒ V=(1/63) L =(1000/63) mL =15.87 ml

Q. What volume of 3 molar $H N O_{3}$ is needed to oxidise $8$ g of $F e^{2 +}$ to $F e^{3 +}$ ?
$H N O_{3} \to NO$

$8$ ml

$15.87$ ml

$32$ ml

$64$ ml

The balanced reaction is
$1/7 3 3 F e^{2 +} + 4 H^{+} + N O_{3}^{-} \to 3 F e^{3 +} + 3 V 1 NO + 2 H_{2} O$
$∴ \frac{3}{17} = \frac{1}{3 V}$
$\Rightarrow V = \frac{1}{63} L$
$= \frac{1000}{63} m L = 15.87 m l$

Q. What volume of 3 molar HNO3​ is needed to oxidise 8 g of Fe2+ to Fe3+? HNO3​→NO

8 ml

15.87 ml

32 ml

64 ml