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  4. What volume of 3 molar HNO3 is needed to oxidise 8 g of Fe2+ to Fe3+? HNO3 → NO

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Q. What volume of 3 molar $HNO_{3}$ is needed to oxidise $8$ g of $Fe^{2+}$ to $Fe^{3+}$?
$HNO_{3} \to NO$

Redox Reactions

Solution:

The balanced reaction is
$\underset{\overset{3}{1/7}}{3F}e^{2+} + 4H^{+} + NO^{-}_{3} \to 3Fe^{3+} + \underset{\overset{1}{3 V}}{NO} + 2H_{2}O$
$\therefore \,\, \frac{3}{17}=\frac{1}{3V}$
$\Rightarrow V=\frac{1}{63} L$
$=\frac{1000}{63} mL =15.87 ml$