What volume of 3 molar HNO3 is needed to oxides 8 g of Fe2 + to Fe3 + ? HNO3 gets converted to NO

Question

What volume of 3 molar HNO3 is needed to oxides 8 g of Fe2 + to Fe3 + ? HNO3 gets converted to NO (A) 8 mL (B) 16 mL (C) 32 mL (D) 64 mL

Tardigrade Admin · Accepted Answer

H overset+ 5N O3 arrow overset+ 2N O n-factor = 5 - 2 = 3 Eq. weight of HNO3=M/3 textmilli texteq text. textof textHNO text3 text= textmilli texteq text. textof textFe text2+ or 3× 3× V=(8/56)× 1000 So V=15.87 mL ≅ text16 textmL

Q. What volume of 3 molar $H N O_{3}$ is needed to oxides 8 g of $F e^{2 +}$ to $F e^{3 +}$ ? $H N O_{3}$ gets converted to NO

8 mL

16 mL

32 mL

64 mL

$H NO + 5_{3} \to NO + 2$
n-factor = 5 - 2 = 3
Eq. weight of $H N O_{3} = M /3$
$milli eq . of HNO_{3} = milli eq . of Fe^{2+}$
or $3 \times 3 \times V = \frac{8}{56} \times 1000$
So $V = 15.87 m L$
$≅ 16 mL$

Q. What volume of 3 molar HNO3​ is needed to oxides 8 g of Fe2+ to Fe3+ ? HNO3​ gets converted to NO