Question

What volume of $0.4MFeC{l}_3.6H_{2}O$ will contain $600mg$ of $F{e}^{3+}$ ?

Answer 1

Answer: 26.78

Molarity $=\frac{n\times 1000}{V(ml)}$
$V=\frac{n\times 1000}{M}$
$=\frac{600\times 10^{-3}\times 1000\times 10}{0.4\times 56}$
$=26.78ml$