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Q. What volume of $0.4\, M \,FeCl _{3} .6 H _{2} O$ will contain $600\, mg$ of $Fe ^{3+}$ ?

Some Basic Concepts of Chemistry

Solution:

Molarity $=\frac{ n \times 1000}{ V ( ml )}$
$V =\frac{ n \times 1000}{ M }$
$=\frac{600 \times 10^{-3} \times 1000 \times 10}{0.4 \times 56}$
$=26.78 \,ml$