What volume of 0.1 N oxalic acid solution can be reduced by 250 g of an 8 percent by weight KMnO 4 solution?

Question

What volume of 0.1 N oxalic acid solution can be reduced by 250 g of an 8 percent by weight KMnO 4 solution? (A) 6.3 litre (B) 12.6 litre (C) 25.2 litre (D) 0.63 litre

Tardigrade Admin · Accepted Answer

Meq. of oxalic acid = Meq. of KMnO 4 V × 0.1=(250 × 8/100 × 31.6) × 1000=6.3 litre

Q. What volume of 0.1 N oxalic acid solution can be reduced by $250 g$ of an 8 percent by weight $K M n O_{4}$ solution?

6.3 litre

12.6 litre

25.2 litre

0.63 litre

Meq. of oxalic acid $=$ Meq. of $K M n O_{4}$

$V \times 0.1 = \frac{250 \times 8}{100 \times 31.6} \times 1000 = 6.3$ litre

Q. What volume of 0.1 N oxalic acid solution can be reduced by 250g of an 8 percent by weight KMnO4​ solution?