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  4. What volume of 0.1 N oxalic acid solution can be reduced by 250 g of an 8 percent by weight KMnO 4 solution?

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Q. What volume of 0.1 N oxalic acid solution can be reduced by $250\, g$ of an 8 percent by weight $KMnO _{4}$ solution?

Redox Reactions

Solution:

Meq. of oxalic acid $=$ Meq. of $KMnO _{4}$

$V \times 0.1=\frac{250 \times 8}{100 \times 31.6} \times 1000=6.3$ litre