What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure

Question

What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure (A) 1.7 (B) 1.4 (C) 1.2 (D) 2.7

Tardigrade Admin · Accepted Answer

From the formula, the minimum refractive index is μ m=( sin i/ sin r)=( sin 90° / sin 45° ) =(1/1/√2) =√2=1.414 =1.4

Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure

1.7

1.4

1.2

2.7

From the formula, the minimum refractive index is $μ_{m} = \frac{s i n i}{s i n r} = \frac{s i n 90 ^{\circ}}{s i n 45 ^{\circ}}$ $= \frac{1}{1/ 2}$ $= 2 = 1.414$ $= 1.4$

Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure

1.7

1.4

1.2

2.7

From the formula, the minimum refractive index is μm​=sinrsini​=sin45∘sin90∘​ =1/2​1​ =2​=1.414 =1.4

From the formula, the minimum refractive index is $μ_{m} = \frac{s i n i}{s i n r} = \frac{s i n 90 ^{\circ}}{s i n 45 ^{\circ}}$ $= \frac{1}{1/ 2}$ $= 2 = 1.414$ $= 1.4$