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Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figurePhysics Question Image

JamiaJamia 2012

Solution:

From the formula, the minimum refractive index is $ {{\mu }_{m}}=\frac{\sin i}{\sin r}=\frac{\sin 90{}^\circ }{\sin 45{}^\circ } $ $ =\frac{1}{1/\sqrt{2}} $ $ =\sqrt{2}=1.414 $ $ =1.4 $