What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure :

Question

What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure : (A) 1.7 (B) 1.4 (C) 1.2 (D) 2.7

Tardigrade Admin · Accepted Answer

From the formula, the minimum refractive index is μm=( sin i/ sin r)=( sin 90°/ sin 45°) =(1/1 / √2) =√2=1.414=1.4

Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure :

1.7

1.4

1.2

2.7

From the formula, the minimum refractive index is
$μ_{m} = \frac{s i n i}{s i n r} = \frac{s i n 9 0 ^{\circ}}{s i n 4 5 ^{\circ}}$
$= \frac{1}{1/ 2} = 2 = 1.414 = 1.4$

Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure :

1.7

1.4

1.2

2.7

From the formula, the minimum refractive index is μm​=sinrsini​=sin45∘sin90∘​ =1/2​1​=2​=1.414=1.4

From the formula, the minimum refractive index is
$μ_{m} = \frac{s i n i}{s i n r} = \frac{s i n 9 0 ^{\circ}}{s i n 4 5 ^{\circ}}$
$= \frac{1}{1/ 2} = 2 = 1.414 = 1.4$