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Q. What should be the minimum value of refractive index of the material of the prism for the reflections to take place as shown in the figure :Physics Question Image

Uttarkhand PMTUttarkhand PMT 2006

Solution:

From the formula, the minimum refractive index is
$\mu_{m}=\frac{\sin i}{\sin r}=\frac{\sin 90^{\circ}}{\sin 45^{\circ}}$
$=\frac{1}{1 / \sqrt{2}} =\sqrt{2}=1.414=1.4$