Question

What should be the equivalent weight of phosphorous acid, if $P=31;O=16;H=1?$

• A. 82
• B. 20.5
• C. 41
• D. None of these

Answer 1

Answer: (C)

The acid is dibasic.

Molecular weight of $H_{3}P{O}_3=3+31+48=82$

$\therefore$ Equivalent weight $=\frac{\text{ Molecular weight }}{\text{ Basicity }}=\frac{82}{2}=41$