What is the value of capacitance if the thin metallic plate is introduced between two parallel plates of area A and separated at distance d?

Question

What is the value of capacitance if the thin metallic plate is introduced between two parallel plates of area A and separated at distance d? (A) (ε0 A/d) (B) (2 ε0 A/d) (C) (4 ε0 A/d) (D) (ε0 A/2d)

Tardigrade Admin · Accepted Answer

When a metallic slab is inserted between the plates, capacitance C = (ε0 A/d - t). Here t = 0 as plate is very thin ∴ C = (ε0 A/d)

Q. What is the value of capacitance if the thin metallic plate is introduced between two parallel plates of area A and separated at distance d?

$\frac{ε _{0} A}{d}$

$\frac{2 ε _{0} A}{d}$

$\frac{4 ε _{0} A}{d}$

$\frac{ε _{0} A}{2 d}$

When a metallic slab is inserted between the plates, capacitance
$C = \frac{ε _{0} A}{d - t} .$ Here $t = 0$ as plate is very thin
$∴ C = \frac{ε _{0} A}{d}$

Q. What is the value of capacitance if the thin metallic plate is introduced between two parallel plates of area A and separated at distance d?

dε0​A​

d2ε0​A​

d4ε0​A​

2dε0​A​

When a metallic slab is inserted between the plates, capacitance C=d−tε0​A​. Here t=0 as plate is very thin ∴C=dε0​A​

$\frac{ε _{0} A}{d}$

$\frac{2 ε _{0} A}{d}$

$\frac{4 ε _{0} A}{d}$

$\frac{ε _{0} A}{2 d}$

When a metallic slab is inserted between the plates, capacitance
$C = \frac{ε _{0} A}{d - t} .$ Here $t = 0$ as plate is very thin
$∴ C = \frac{ε _{0} A}{d}$