Question

What is the value of capacitance if the thin metallic plate is introduced between two parallel plates of area A and separated at distance d?

• A. $\frac{\varepsilon_0 A}{d}$
• B. $\frac{2 \varepsilon_0 A}{d}$
• C. $\frac{4 \varepsilon_0 A}{d}$
• D. $\frac{\varepsilon_0 A}{2d}$

Answer 1

Answer: (A)

When a metallic slab is inserted between the plates, capacitance
$C = \frac{\varepsilon_0 A}{d - t}.$ Here $t = 0$ as plate is very thin
$\therefore C = \frac{\varepsilon_0 A}{d}$