Question

What is the total number of electrons present in $1.6g$ of methane?

• A. $6.023\times 10^{23}$
• B. $16$
• C. $12.04\times 10^{23}$
• D. $6.023\times 10^{24}$

Answer 1

Answer: (A)

$1$ mole of $C{H}_4=16g$
$16g$ of $C{H}_4$ contain $10$ electrons
$1.6g$ of $C{H}_4$ contain $\frac{10}{16}\times 1.6\times 6.023\times 10^{23}$
$=6.023\times 10^{23}$ electrons