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Q. What is the total number of electrons present in $1.6 \,g$ of methane?

Some Basic Concepts of Chemistry

Solution:

$1$ mole of $CH_4 = 16\, g$
$ 16\, g$ of $CH_4$ contain $10$ electrons
$ 1.6\, g$ of $CH_4$ contain $\frac{10}{16} \times 1.6 \times 6.023 \times 10^{23}$
$ = 6.023 \times 10^{23}$ electrons