What is the total mass of formed soluble manganese compound (in gram) by 3 moles of K2MnO4 with aqueous solution having 2 moles of H2SO4 ? (atomic weight of Mn=55,K=39,S=32 , O=16,H=1 )

Question

What is the total mass of formed soluble manganese compound (in gram) by 3 moles of K2MnO4 with aqueous solution having 2 moles of H2SO4 ? (atomic weight of Mn=55,K=39,S=32 , O=16,H=1 ) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

3K2MnO4+2H2SO4 arrow 2KMnO4+MnO2+ 2K2SO4+2H2O mass of Mn compounds =2× (158/KMnO4) =316.00g

Q. What is the total mass of formed soluble manganese compound (in gram) by $3$ moles of $K_{2} M n O_{4}$ with aqueous solution having $2$ moles of $H_{2} S O_{4}$ ? (atomic weight of $M n = 55, K = 39, S = 32$ , $O = 16, H = 1$ )

$3 K_{2} M n O_{4} + 2 H_{2} S O_{4} \to 2 K M n O_{4} + M n O_{2} +$ $2 K_{2} S O_{4} + 2 H_{2} O$
mass of $M n$ compounds $= 2 \times \frac{158}{K M n O _{4}}$
$= 316.00 g$

Q. What is the total mass of formed soluble manganese compound (in gram) by 3 moles of K2​MnO4​ with aqueous solution having 2 moles of H2​SO4​ ? (atomic weight of Mn=55,K=39,S=32 , O=16,H=1 )

3K2​MnO4​+2H2​SO4​→2KMnO4​+MnO2​+ 2K2​SO4​+2H2​O mass of Mn compounds =2×KMnO4​158​ =316.00g

Q. What is the total mass of formed soluble manganese compound (in gram) by $3$ moles of $K_{2} M n O_{4}$ with aqueous solution having $2$ moles of $H_{2} S O_{4}$ ? (atomic weight of $M n = 55, K = 39, S = 32$ , $O = 16, H = 1$ )

$3 K_{2} M n O_{4} + 2 H_{2} S O_{4} \to 2 K M n O_{4} + M n O_{2} +$ $2 K_{2} S O_{4} + 2 H_{2} O$
mass of $M n$ compounds $= 2 \times \frac{158}{K M n O _{4}}$
$= 316.00 g$