Question

What is the total mass of formed soluble manganese compound (in gram) by $3$ moles of $K_{2}MnO_{4}$ with aqueous solution having $2$ moles of $H_{2}SO_{4}$ ? (atomic weight of $Mn=55,K=39,S=32$ , $O=16,H=1$ )

Answer 1

$3K_{2}MnO_{4}+2H_{2}SO_{4} \rightarrow 2KMnO_{4}+MnO_{2}+$ $2K_{2}SO_{4}+2H_{2}O$
mass of $Mn$ compounds $=2\times \frac{158}{KMnO_{4}}$
$=316.00g$