What is the self-inductance of a coil which produces 5 mV when the current changes from 3 ampere to 2 ampere in one millisecond?

Question

What is the self-inductance of a coil which produces 5 mV when the current changes from 3 ampere to 2 ampere in one millisecond? (A) 5000 henry (B) 5 mili-henry (C) 50 henry (D) 5 henry

Tardigrade Admin · Accepted Answer

∈=-L(di/dt) L=(-∈/(di)dt)=(-5×10-3/(2-3))H=5 mH

Q. What is the self-inductance of a coil which produces 5 mV when the current changes from 3 ampere to 2 ampere in one millisecond?

5000 henry

5 mili-henry

50 henry

5 henry

$\in= - L \frac{d i}{d t}$
$L = \frac{- \in}{\frac{d i}{d t}} = \frac{- 5 \times 1 0 ^{- 3}}{( 2 - 3 )} H = 5$ mH

Q. What is the self-inductance of a coil which produces 5 mV when the current changes from 3 ampere to 2 ampere in one millisecond?

5000 henry

5 mili-henry

50 henry

5 henry

∈=−Ldtdi​ L=dtdi​−∈​=(2−3)−5×10−3​H=5 mH

$\in= - L \frac{d i}{d t}$
$L = \frac{- \in}{\frac{d i}{d t}} = \frac{- 5 \times 1 0 ^{- 3}}{( 2 - 3 )} H = 5$ mH