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Q. What is the self-inductance of a coil which produces 5 mV when the current changes from 3 ampere to 2 ampere in one millisecond?

AIPMTAIPMT 1993

Solution:

$\in=-L\frac{di}{dt}$
$L=\frac{-\in}{\frac{di}{dt}}=\frac{-5\times10^{-3}}{(2-3)}H=5$ mH