Question

What is the percentage of cation in ammonium dichromate ?

• A. 14.29%
• B. 80%
• C. 50.05%
• D. 20.52%

Answer 1

Answer: (A)

Molecular formula of ammonium dichromate is
$(N{H}_4{)}_{2}C{r}_2{O}_7$.
Molecular weight = 2 $\times$ (14 + 4 )+ 2 $\times$ 52 + 7 $\times$ 16
= 252
Number of parts by weight of cation, i.e., $N{H}_4^{+}$
= 2 $\times$ (14 + 4) =36
% of $N{H}_4^{+}=\frac{36}{252}\times 100=14.29$ %