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Q. What is the percentage of cation in ammonium dichromate ?

KEAMKEAM 2006Some Basic Concepts of Chemistry

Solution:

Molecular formula of ammonium dichromate is
$(NH_4 )_2Cr_2O_7$.
Molecular weight = 2 $\times$ (14 + 4 )+ 2 $\times$ 52 + 7 $\times$ 16
= 252
Number of parts by weight of cation, i.e., $NH_4^+$
= 2 $\times$ (14 + 4) =36
% of $NH^+_4 = \frac{36}{252} \times 100 = 14.29 $ %