Question

What is the magnetic moment for $M{n}^{2+}$ ion in low spin state?

• A. 5.90 BM
• B. 8.90 BM
• C. 2.8 BM
• D. 1.73 BM

Answer 1

Answer: (D)

: For $M{n}^{2+}$ ion in low spin state, number of unpaired electrons = 1. Magnetic moment $=n\sqrt{n(n+2)}=\sqrt{1\times 3}=1.73BM.$