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  4. What is the magnetic moment for Mn2+ ion in low spin state?

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Q. What is the magnetic moment for $ M{{n}^{2+}} $ ion in low spin state?

AMUAMU 1999

Solution:

: For $ M{{n}^{2+}} $ ion in low spin state, number of unpaired electrons = 1. Magnetic moment $ =n\sqrt{n(n+2)}=\sqrt{1\times 3}=1.73\text{ }BM. $